How do you find is there any element appear more than N 2 times?

How do you find is there any element appear more than N 2 times?

Approach: The basic solution is to have two loops and keep track of the maximum count for all different elements. If maximum count becomes greater than n/2 then break the loops and return the element having maximum count.

What will be the time complexity for printing all the elements of an linear array of size n?

Given an array of size n, find all elements in array that appear more than n/k times. First, sort all elements using a O(nLogn) algorithm. Once the array is sorted, we can find all required elements in a linear scan of array. So overall time complexity of this method is O(nLogn) + O(n) which is O(nLogn).

How to find sequences of given length n?

Given two integers m & n, find the number of possible sequences of length n such that each of the next element is greater than or equal to twice of the previous element but less than or equal to m. Input : m = 10, n = 4 Output : 4 There should be n elements and value of last element should be at-most m.

Which is the best number Sequence Calculator?

1 Arithmetic Sequence Calculator 2 Geometric Sequence Calculator 3 Fibonacci Sequence Calculator. In mathematics, a sequence is an ordered list of objects. Accordingly, a number sequence is an ordered list of numbers that follow a particular pattern.

What is the number of terms in a sequence called?

Each of the individual elements in a sequence are often referred to as terms, and the number of terms in a sequence is called its length, which can be infinite. In a number sequence, order of the sequence is important, and depending on the sequence, it is possible for the same terms to appear multiple times.

How to find the sum of a Fibonacci sequence?

Using the same geometric sequence above, find the sum of the geometric sequence through the 3 rd term. A Fibonacci sequence is a sequence in which every number following the first two is the sum of the two preceding numbers.

How do you find is there any element appear more than n 2 times?

How do you find is there any element appear more than n 2 times?

Approach: The basic solution is to have two loops and keep track of the maximum count for all different elements. If maximum count becomes greater than n/2 then break the loops and return the element having maximum count.

What is the majority element?

The majority element is an element in an array that occurs more than (size/2) times in an array (where size​ is the number of elements stored in an array).

What is 2D array in C?

The two-dimensional array can be defined as an array of arrays. The 2D array is organized as matrices which can be represented as the collection of rows and columns. However, 2D arrays are created to implement a relational database lookalike data structure.

How to find a majority element in an array?

A majority element in an array A of size N is an element that appears more than N/2 times in the array. Input: N = 3 A [] = {1,2,3} Output: -1 Explanation: Since, each element in {1,2,3} appears only once so there is no majority element.

What is the frequency of the majority element?

Input : {3, 3, 4, 2, 4, 4, 2, 4, 4} Output : 4 Explanation: The frequency of 4 is 5 which is greater than the half of the size of the array size. Input : {3, 3, 4, 2, 4, 4, 2, 4} Output : No Majority Element Explanation: There is no element whose frequency is greater than the half of the size of the array size.

How to make an element a majority element?

Sort the array and create a variable count and previous, prev = INT_MIN. Traverse the element from start to end. If the current element is equal to the previous element increase the count. Else set the count to 1. If the count is greater than half the size of array, print the element as majority element and break.

When to break the loop for majority element?

If maximum count becomes greater than n/2 then break the loops and return the element having maximum count. If the maximum count doesn’t become more than n/2 then the majority element doesn’t exist. Traverse through the array from start to end. For every element in the array run another loop to find the count of similar elements in the given array.