How do you find the intersection of two sorted arrays?

How do you find the intersection of two sorted arrays?

To find intersection of 2 sorted arrays, follow the below approach :

  1. Use two index variables i and j, initial values i = 0, j = 0.
  2. If arr1[i] is smaller than arr2[j] then increment i.
  3. If arr1[i] is greater than arr2[j] then increment j.
  4. If both are same then print any of them and increment both i and j.

What is union in C?

Union is an user defined datatype in C programming language. It is a collection of variables of different datatypes in the same memory location. We can define a union with many members, but at a given point of time only one member can contain a value. C unions are used to save memory.

What is the symbol of intersection?

∩
The symbol we use for the intersection is ∩. The word that you will often see that indicates an intersection is “and”. Find A∩B.

How to find intersection of two sorted arrays?

To find intersection of 2 sorted arrays, follow the below approach : 2) If arr1 [i] is smaller than arr2 [j] then increment i. 3) If arr1 [i] is greater than arr2 [j] then increment j. 4) If both are same then print any of them and increment both i and j. Below is the implementation of the above approach :

How to use std set intersection in C + +?

Template : OutputIterator set_intersection (InputIterator1 first1, InputIterator1 last1, InputIterator2 first2, InputIterator2 last2, OutputIterator result); Parameters : first1, last1 Input iterators to the initial and final positions of the first sorted sequence.

How is the intersection of two sets formed?

The intersection of two sets is formed only by the elements that are present in both sets. The elements copied by the function come always from the first range, in the same order. The elements in the both the ranges shall already be ordered.

Do you count duplicates in the intersection list?

The intersection should not count duplicate elements. To handle duplicates just check whether current element is already present in intersection list. Below is the implementation of this approach. Another approach that is useful when difference between sizes of two given arrays is significant.