How do you find the middle of a linked list?

How do you find the middle of a linked list?

Solution Steps

1. Create a pointer p , pointing to the head.
2. Iterate over the linked list until p reaches to the end of the linked list, thereby find the length of the list.
3. Set p to head again. Now, increment p length/2 times. Now, the p is at the middle of the linked list node. Return the value at p.

How do you find the middle element of a linked list in Python?

Python program to find middle of a linked list using one…

1. Method 1: Traverse the whole linked list and count the no. of nodes.
2. Method 2: Traverse linked list using two pointers. Move one pointer by one and other pointer by two.
3. Method 3: Initialized the temp variable as head. Initialized count to Zero.

How do you find the middle element of an arrayList?

So, presuming you want the “middle” element (i.e. item 3 in a list of 5 items — 2 items on either side), it’d be this: Object item = arrayList. get((arrayList. size()/2)+1);

How do you find the middle element of a list?

We can check it by comparing the count of all smaller and bigger elements in the list. If for a number, the list contains an equal amount of smaller and bigger numbers, it will be the middle number in that list. The main problem of this solution is that we need to iterate through the list multiple times.

How do you find the middle element in a linked list without using count?

Method 2: Traverse linked list using two pointers. Move one pointer by one and the other pointers by two. When the fast pointer reaches the end slow pointer will reach the middle of the linked list.

How do you add an element in the middle of the linked list?

Algorithm

1. Create a class Node which has two attributes: data and next.
2. Create another class InsertMid which has three attributes: head, tail, and size that keep tracks of a number of nodes present in the list.
3. addNode() will add a new node to the list:
4. addInMid() will add a new node at the middle of the list:

How do you find the middle element of a linked list in one pass in C++?

In order to find middle element of linked list in one pass, you need to maintain two pointers, one increment at each node while other increments after two nodes at a time. By having this arrangement, when first pointer reaches end, second pointer will point to middle element of linked list.

How do you print the middle element of a list?

Print the middle value of the sorted list by accessing the size of the list/2 position. To get the length of a list, we are using len(list) method. len(list) method returns the length of a list. Dividing this value by 2 will give us the middle position.

How do you find the middle element in a circular linked list?

Traverse linked list using two pointers. Move one pointer by one and the other pointers by two. When the fast pointer reaches the end slow pointer will reach the middle of the linked list.

How do you know if a linked list is circular?

To check whether the linked list is circular or not, we will store the header node into some other variable, then traverse the list, if we get null at the next part of any node, then that is not circular, otherwise we will check the next node is same as the stored node or not, if so then that is circular.

How to get middle element of linked list in Java?

We then find the middle element of the linked list in a single loop. Notice the code, Here, we have two variables ptr1 and ptr2. We use these variables to iterate through the linked list. In each iteration, the ptr1 will access the two nodes and the ptr2 will access the single node of the linked list.

How to find middle node in linked list?

Input: LinkedList: 2->4->6->7->5->1 Output: 7 Explanation: Middle of linked list is 7. The task is to complete the function getMiddle() which takes a head reference as the only argument and should return the data at the middle node of the linked list.

How to return middle of the linked list?

876. Middle of the Linked List Given a non-empty, singly linked list with head node head, return a middle node of linked list. If there are two middle nodes, return the second middle node. Input: [1,2,3,4,5] Output: Node 3 from this list (Serialization: [3,4,5] ) The returned node has value 3. (The judge’s serialization of this node is [3,4,5]).

How to get middle element of linked list in one iteration?

In each iteration, the ptr1 will access the two nodes and the ptr2 will access the single node of the linked list. Now, when the ptr1 reaches the end of the linked list, the ptr2 will be in the middle. In this way, we are able to get the middle of linked list in a single iteration.