How do you find the most occurring element in an array?

How do you find the most occurring element in an array?

Algorithm

1. Start.
2. Declare the array.
3. Initialize the array.
4. Call the function that will return the most occurring element.
5. Sort the array first.
6. Traverse the array to count the frequency of each element.
7. Return the element with the highest frequency.
8. Print the element.

What digit between 1 and 1000 is the most frequent?

What digit is the most frequent between the numbers 1 and 1,000 (inclusive)? To solve this riddle you don’t want to manually do all of the math but rather try to figure out a pattern. The most common digit is ‘1.

Which is the most occuring digit in an array of numbers?

If there are N numbers, each with M digits, your solution is using 10 * N * M operations to compute the solution. This is because for each digit (e.g. 0, 1, 2), you look at every digit in every number. But you could make your solution 10 times faster by only looking at each digit once.

How to get the most occurring element in an array?

Most occurring element in an array using c++? I had tried the following code to get most occurring element in an array. It is working well but the only problem is when there are two or more elements having the same number of occurrence and equal to most occurring element, it just shows the first element scanned.

How to find the most frequent number in an array?

I have this Array i wrote a function MostFreq that takes an array of integers and return 2 values : the more frequent number in the array and its frequency check this code i worte what do you think ? is there a better way to do it? LINQ it up. I know this is in VB but you should be able to convert it to C#:

When to write out a random number in an array?

If you have 2 or more digits with the same amount of occurrences write out a random one. For example X [3] = {20; 21; 30}, either write out 0 or 2. I could’ve used dynamic arrays, but that’s not what I’m interested in here.