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How do you find the sum of multiples of a number?
To get the result in O(1) time we can use the formula of summation of n natural numbers. For the above example, a = 4 and N = 23, number of multiples of a, m = N/a(integer division). The multiples are 4, 8, 12, 16, 20.
What is the formula for the sum of numbers?
The formula to calculate the sum of integers is given as, S = n(a + l)/2, where, S is sum of the consecutive integers n is number of integers, a is first term and l is last term.
What is the sum of angle 3 and angle 5?
We multiply 3 times 180 degrees to find the sum of all the interior angles of a pentagon, which is 540 degrees.
How to find the sum of all the multiples of 3 or 5?
Find the sum of all the multiples of 3 or 5 below 1000. The previously posted answer isn’t correct. The statement of the problem is to sum the multiples of 3 and 5 below 1000, not up to and equal 1000. The correct answer is
Is the sum of 3 and 5 equal to 15?
Well, the answer is, 15 can be evenly divide by both 3 & 5. So the products of 15 can also be divided by those number as well! So, when you adding the numbers with Sum Of Three & Sum Of Five there are some numbers (i.e. 15,30,45,60….) which are available at both SUMMATION.
What are the multiples of the number 5?
The multiples of 5 are 5,10,15,20,25,30,35,40,45,…. The intersection of these two sequences is 15,30,45,… The sum of the first numbers 1+2+3+4+…+n is n (n+1)/2. The sum of the first few multiples of k, say k+2k+3k+4k+…+nk must be kn (n+1)/2. Now you can just put these ingredients together to solve the problem.
How to find all the multiples of 3 or 5 below 1000 in Python?
You are overcomplicating things. You just need a list of numbers that are multiples of 3 or 5 which you can get easily with a list comprehension: Or even better use a generator expression instead: Or even better better (courtesy Exelian):