How do you find the sum of the squares of a number?

How do you find the sum of the squares of a number?

Using modulous operator or remainder operator, we will get the last digit of number. Find the square of that digit and sum it up with sum variable and then initialize it to sum variable. Then divide the value (num) with 10 to skip or delete the last digit. For example, if user enters 2346 as input.

What is the sum of squares of numbers?

Sum of Squares Formulas

In Statistics	Sum of Squares: = Σ(xi + x̄)2
In Algebra	Sum of Squares of Two Values: = a2 + b2 = (a + b)2 − 2ab
For “n” Terms	Sum of Squares Formula for “n” numbers = 12 + 22 + 32 ……. n2 = n(n+1)(2n+1)/6

How do you print sum of squares in Python?

python program for sum of squares of n natural numbers

1. n = int(input(“Enter nth number : “))
2. sum = 0.
3. for s in range(1, n+1):
4. sum = sum + (s*s)
5. print(“Sum of squares is : “, sum)

What is the sum of the squares of the digits from 1 to 9?

1+4+9+16+25+36+49+64+81=285 is sum of squares of digit from 1 to 9.

What is the sum of squares of n natural numbers?

Sum of Squares of n Natural Numbers Formula If we need to calculate the sum of squares of n consecutive natural numbers, the formula is Σn2 = n×(n+1)×(2n+1)6 n × ( n + 1 ) × ( 2 n + 1 ) 6 . It is easy to apply the formula when the value of n is known. Let us prove this true using the known algebraic identity.

What is the formula of sum of squares of odd numbers?

Sum of Squares of First n Odd Numbers

Sum of:	Formula
Squares of three numbers	x2 + y2+z2 = (x+y+z)2-2xy-2yz-2xz
Squares of first ‘n’ natural numbers	Σn2 = [n(n+1)(2n+1)]/6
Squares of first even natural numbers	Σ(2n)2 = [2n(n+1)(2n+1)]/3
Squares of first odd natural numbers	Σ(2n-1)2 =[n(2n+1)(2n-1)]/3

What is the sum of squares of first 100 natural numbers?

So, the sum of squares of first n natural numbers where n = 100 is 338350.

What is the formula for sum of squares of first n natural numbers?

Sum of Squares of n Natural Numbers Formula If we need to calculate the sum of squares of n consecutive natural numbers, the formula is Σn2 = n×(n+1)×(2n+1)6 n × ( n + 1 ) × ( 2 n + 1 ) 6 . It is easy to apply the formula when the value of n is known.

What is the sum of the number from 1 to 10?

The answer is 55.

What is the formula for sum of cubes?

The sum of cubes formula is one of the important algebraic identity. It is represented by a3 + b3 and is read as a cube plus b cube. The sum of cubes (a3 + b3) formula is expressed as a3 + b3 = (a + b) (a2 – ab + b2).

What is the formula for the sum of squares of first n numbers?