Contents
How do you replace a line using sed?
Find and replace text within a file using sed command
- Use Stream EDitor (sed) as follows:
- sed -i ‘s/old-text/new-text/g’ input.
- The s is the substitute command of sed for find and replace.
- It tells sed to find all occurrences of ‘old-text’ and replace with ‘new-text’ in a file named input.
How do you sed a variable?
Related
- \t string with sed.
- Replacing a string by a file using Sed.
- use sed command with variable.
- sed the string and hold the value in new variable.
- Use sed to replace a string that contains characters with specials meanings to sed.
- Escaping a literal string for sed.
- Cutting a string using sed.
How do you give a variable in sed?
3 Answers
- Use double quotes so that the shell would expand variables.
- Use a separator different than / since the replacement contains /
- Escape the $ in the pattern since you don’t want to expand it.
How to use sed to replace specific line with a?
I have a variable called line=1 and a variable string substitute=hello1. I want to replace the string in the line described by the variable line with my new string variable called substitute. How would I use sed to do this? Or awk? If thats what you are in to, as long as I can input variables that I can change in a while loop.
How to use sed to find string in files?
To avoid issues with files containing space in their names, use the -print0 option, which tells find to print the file name, followed by a null character and pipe the output to sed using xargs -0 : find. -type f -print0 | xargs -0 sed -i ‘s/foo/bar/g’ To exclude a directory, use the -not -path option.
How to replace old line variable with new line variable?
The contents of this variable looks like this: I have created a second variable called new_line that is similar to old_line but with some modifications in the text. I want to substitute the contents of old_line with the contents of new_line using sed. So far I have the following, but it doesn’t work:
How to replace a string in a file with a variable?
I need to replace a string in a file by another string which is stored in a variable. replaces a string but what if destination String was a combination of a hard coded string and a variable? The latter doesn’t work, since $myString is not interpreted as a variable.