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How do you reverse a String without affecting special characters?
Simple Solution:
- Create a temporary character array say temp[].
- Copy alphabetic characters from the given array to temp[].
- Reverse temp[] using standard string reversal algorithm.
- Now traverse input string and temp in a single loop.
What is the complexity of reversing a String with n characters?
This algorithm only requires one extra character of memory to facilitate the swapping of characters. The time complexity of this algorithm is O(n/2)I mean O(n) where n is the length of String. Ideally, whenever you need to reverse a String in your application, you should be using the reverse() method of StringBuilder.
How do you reverse a String without moving space from its original position?
Write a Java program to reverse a given string with preserving the position of spaces?
- public class ReverseStringPreserveSpace {
- static void reverseString(String input) {
- char[] inputArray = input.toCharArray();
- char[] result = new char[inputArray.length];
- for (int i = 0; i < inputArray.length; i++) {
How do I reverse a character in a String?
Strings can be reversed using slicing. To reverse a string, we simply create a slice that starts with the length of the string, and ends at index 0. The slice statement means start at string length, end at position 0, move with the step -1 (or one step backward).
How do I remove special characters from a string in Python?
Remove Special Characters From the String in Python
- Remove Special Characters From the String in Python Using the str.isalnum() Method.
- Remove Special Characters From the String in Python Using filter(str.isalnum, string) Method.
- Remove Special Characters From the String in Python Using Regular Expression.
What is the time complexity of reverse function in C++?
reverse() is a predefined function in header file algorithm. It is defined as a template in the above mentioned header file. It reverses the order of the elements in the range [first, last) of any container. The time complexity is O(n).