Contents
How do you use a variable outside a loop in Python?
- you have to set the variable a outside the loop. – Murillio4.
- a = None or a = “” before with line. – user1935024.
- You missed colon in the if line. – volcano.
- @Murillio4 Not necessarily; there’s only one scope in the posted code, but a is not guaranteed to be set by the code. – chepner.
- @mohaned thanks! for your answer.
What is the scope of a for loop index variable?
The scoping semantics of the for loop dictate that after each execution of the loop, the object that was created during that iteration will be destroyed. In C/C++, the scope of a variable declared in a for or while loop (or any other bracketed block, for that matter) is from the open bracket to the close bracket.
How to access a variable after a for loop?
You can easily access it after your for loop but If you use it as a simple variable var randAd;then you’ll get the last variable always (it overwrites). So initialize it as an array and push every element inside loop before outputting it.
Can you access an object outside of a loop?
You can only access an object if it was declared in the same scope or an enclosing scope. That’s the techno babble explanation. 🙂 What it means is that if you declare something inside a loop, you can’t use it outside the loop because the body of a loop counts …
How to access randad outside the for loop?
If you want to access every element of randAd outside the for loop try like this var randAd = []; to initialize it as an array. You can easily access it after your for loop but If you use it as a simple variable var randAd; then you’ll get the last variable always (it overwrites).
How to get a variable outside the loop in Python?
To handle this more gracefully, you should assign a default value to a before the loop: a = None with open (‘test’, ‘r’) as f: You can then check if it’s None after the loop: if a is not None: EDIT: It simultaneously solves the problem of not printing a , if you did not find what you were looking for