How many and gates are required for a 3 to 8 decoder?

How many and gates are required for a 3 to 8 decoder?

Using the above expressions, the circuit of a 3 to 8 decoder can be implemented using three NOT gates and eight 3-input AND gates as shown in fig (1). The three inputs A, B and C are decoded into eight outputs, each output representing one of the midterms of the 3-input variables.

How many 2 to 4 decoder and AND gates are required to design a 3 to 8 decoder?

Therefore, we require two 2 to 4 decoders for implementing one 3 to 8 decoder.

How many and gates are in a decoder?

four AND gates
This simple example above of a 2-to-4 line binary decoder consists of an array of four AND gates. The 2 binary inputs labelled A and B are decoded into one of 4 outputs, hence the description of 2-to-4 binary decoder. Each output represents one of the miniterms of the 2 input variables, (each output = a miniterm).

How many logic gates do we need for a 2 to 4 decoder?

four
The first-stage of 2-to-4 decoder requires four 2-input AND gates, because total number of logic combinations, that can be formed with two variables is four. Each logical combination of two variables A & B are given to input ports of respective AND gates.

How to design a 3 to 8 decoder?

Using only three 2-to-4 decoders with enable and no other additional gates, implement a 3-to-8 decoder with enable. The inputs of the resulting 3-to-8 decoder should be labeled X [2..0] for the code input and E for the enable input. the outputs should be labeled Y [7..0]. Here’s my current solution.

How many inputs are in a 2 to 4 line decoder?

We have discussed above that 2 to 4 line decoder includes two inputs and four outputs. So, in 3 lines to 8 line decoder, it includes three inputs like A2, A1 & A0 and 8 outputs from Y7 – Y0. The following formula is used to implementation of higher-order decoders with the help of low order decoders

Can you use two 3×8 decoders with 16 gates?

If you use two 3×8 decoders you need not use 16 AND gates, and If you want to use AND gates only, then think about the internal circuitry of a decoder, think of this diagram , and you can easily construct using AND gates.

How are the two squares of a decoder connected?

the two squares are two 3×8 decoders with enable lines. the three selection lines of each decoders are connected together as common line (X,Y,Z) , the enable lines are ACTIVE LOW, they are also connected together with a common line W , but the second one having a NOT gate connected within. So, there are now 4 selection inputs i.e W,X,Y,Z.