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How to collect the exit codes of parallel processes?
Make a list of commands to run and put them in the file list: Run all the commands in parallel and collect the exit codes in the file job.log: this is the generic script you’re looking for.
How to run shell scripts in parallel in Bash?
To run script in parallel in bash, you must send individual scripts to background. So the loop will not wait for the last process to exit and will immediately process all the scripts.
Can you print the exit code of wait alone?
You can probably get away with using wait alone almost all the time. If you had a good way to identify the commands, you could print their exit code to a tmp file and then access the specific file you’re interested in: Don’t forget to remove the tmp files.
How to get the exit status of a background process?
If a job spec is given, all processes in the job are waited for. If no arguments are given, all currently active child processes are waited for, and the return status is zero. If the -n option is supplied, wait waits for any job to terminate and returns its exit status.
How to check the exit status of a shell?
If the -n option is supplied, wait waits for any job to terminate and returns its exit status. If neither jobspec nor pid specifies an active child process of the shell, the return status is 127.
Is there a way to run a script in parallel?
It’s really as easy as that. When you run the script, all three processes will be forked in parallel, and the script will wait until all three have completed before exiting. Anything after the wait command will execute only after the three forked processes have exited.
When to capture the exit code of a spawned process?
The loop also echoes some messages to stdout indicating progress of the script. Exit the loop when the spawned command terminates. Capture and report the exit code of the spawned process. Can someone give me pointers to accomplish this?