Contents
- 1 How to edit next line after pattern using SED?
- 2 Is there a way to skip a line in SED?
- 3 How to skip the next line in AWK?
- 4 How to replace the next line in Linux?
- 5 How to pass the output of grep to SED?
- 6 When to use sed to insert lines after match?
- 7 When to use the replacement flag in SED?
- 8 How to use sed to find string in files?
How to edit next line after pattern using SED?
Using sed, how do I search for a line ending with foo and then edit the next line if it starts with #bar? Or put another way, I want to remove a comment # from the next line if it starts with #bar and the previous line ends in foo.
Is there a way to skip a line in SED?
–skip >= 0 decrements the skip count and takes action if it is (still) >= 0, implying that the line at hand should be skipped. Only non-matching and non-skipped lines reach this command.
How to skip the next line in AWK?
-v regex=”$regex” -v count=”$count” defines awk variables based on shell variables of the same name. { skip=count; next } initializes the skip count and proceeds to the next line, effectively skipping the matching line; in the 2nd solution, the print before next ensures that it is not skipped.
How to skip lines in a pattern Stack Overflow?
Assume that the regular expression to use for finding matching lines is stored in shell variable $regex, and the count of lines to skip in $count. If the matching line should also be skipped ( $count + 1 lines are skipped):
How to find matching text and replace next line?
The file looks like this: This might work for you (GNU sed): !b negates the previous address (regexp) and breaks out of any processing, ending the sed commands, n prints the current line and then reads the next into the pattern space, c changes the current line to the string following the command.
How to replace the next line in Linux?
!b negates the previous address (regexp) and breaks out of any processing, ending the sed commands, n prints the current line and then reads the next into the pattern space, c changes the current line to the string following the command. Using sed, replacing the next line after the pattern ‘Unix’ with ‘hi’: For your specific question: It works.
How to pass the output of grep to SED?
One possibility would be to pass the output of grep to a separate sed filter. You could make sed print the line number (with the = command) when it finds a match and do further postprocessing. It would probably be clearer to use awk.
When to use sed to insert lines after match?
And this might have slight variations depending on your POSIX compliance, but if you want to insert multiple lines, you can use ‘ ’ as shown below. https://stackoverflow.com/questions/15559359/insert-line-after-first-match-using-sed (insert after match)
How to insert a line before or after a match?
In these examples, we will be dealing with a text file named “text.txt” that contains the following content: The simplest case is replacing an entire line by finding the line that starts with the match. Then we have the case where we need to insert a line after the match.
What’s the best way to substitute a file in SED?
-i – By default, sed writes its output to the standard output. This option tells sed to edit files in place. If an extension is supplied (ex -i.bak), a backup of the original file is created. s – The substitute command, probably the most used command in sed.
When to use the replacement flag in SED?
When the replacement flag is provided, all occurrences are replaced. INPUTFILE – The name of the file on which you want to run the command. It is a good practice to put quotes around the argument so the shell meta-characters won’t expand.
How to use sed to find string in files?
To avoid issues with files containing space in their names, use the -print0 option, which tells find to print the file name, followed by a null character and pipe the output to sed using xargs -0 : find. -type f -print0 | xargs -0 sed -i ‘s/foo/bar/g’ To exclude a directory, use the -not -path option.