How to find minimum number of operations required to convert x to y?
The task is to find out minimum number of operation required to convert number x into y using only above two operations. We can apply these operations any number of times. Input : x = 4, y = 7 Output : 2 We can transform x into y using following two operations.
How to reduce a number to one by performing given operations?
Reduce a number to 1 by performing given operations. Given a number N. The task is to reduce the given number N to 1 in the minimum number of steps. You can perform any one of the below operations in each step. Operation 1: If the number is even then you can divide the number by 2.
Can a decrement of 1 result in an even number?
It is clear with little observation that performing an increment of 1 or a decrement of 1 on an odd number can result in an even number, one of it divisible by 4.
Is it possible to convert m to n using subtractions?
The idea is based on below facts. 1) If m is less than 0 and n is greater than 0, then not possible. 2) If m is greater than n, then we can reach n using subtractions only. 3) Else (m is less than n), we must do m*2 operations.
How to reduce the number of operations to 1?
If the number modulo 3 is 1, decrement it by 1. If the number modulo 3 is 2, increment it by 1. There is an exception when the number is equal to 2, in this case the number should be decremented by 1. Repeat the above steps until the number is greater than 1 and print the count of operations performed in the end.
What’s the minimum number of operations to divide n by 3?
If N is a multiple of 3, you can divide N by 3. The minimum number of operations required is 2. The minimum number of operations required is 3. Recommended: Please try your approach on {IDE} first, before moving on to the solution.
What’s the minimum number of operations required to decrement N?
Decrement N by 1. Increment N by 1. If N is a multiple of 3, you can divide N by 3. The minimum number of operations required is 2. The minimum number of operations required is 3.