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How to find sum of all the levels in a binary search tree?
Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: Find the height of the given binary tree then the number of levels in the tree will be levels = height + 1. Now create an array sum [] of size levels where sum [i] will store the sum of all the nodes at the ith level.
How to get sum of all the levels in a tree?
In order to update this array, write a recursive function that add the current node’s data at sum [level] where level is the level of the current node and then recursively call the same method for the child nodes with level as level + 1. Below is the implementation of the above approach:
How to calculate sum of nodes at k-th level?
1. Input ‘tree’ in string format and level k 2. Initialize level = -1 and sum = 0 3. for each character ‘ch’ in ‘tree’ 3.1 if ch == ‘ (‘ then –> level++ 3.2 else if ch == ‘)’ then –> level– 3.3 else if level == k then sum = sum + (ch-‘0’) 4.
How to calculate the time complexity of a binary tree?
Therefore, the time complexity is O (N). Auxiliary Space: O (w) where w is the maximum width of the tree. In level order traversal, a queue is maintained whose maximum size at any moment can go up to the maximum width of the binary tree.
How many nodes in a balanced binary search tree?
For example, a balanced binary search tree with 5 nodes, the above formula gives an answer of 3 which is not true because a tree with 5 nodes can contain a maximum nodes of 4 nodes at the last level. So I am guessing he meant full balanced binary search tree.
What’s the minimum number of nodes in a tree?
That would be the maximum number of leaf nodes for a given tree height H. The minimum number of nodes at a given height is 1 (cannot be zero, because then the tree height would be reduced by one). H = 1, L = 1, N = 1 H = 2, L = 2, N = 3 H = 3, L = 4, N = 7 H = 4, L = 8, N = 15