How to generate a censored sample in R?

How to generate a censored sample in R?

For instance lets have the n = 3, shape = 3, scale = 1 and the censoring rate = .15, and the censoring time = .88. I know how to generate a Weibull sample but I do not know how to generate a censored data that have type I right-censored in R.

How to generate right censored data using Min?

To generate right censored data using censoring time = 0.88, you’d just use the min function: However, I’m not entirely sure what you mean when you say, ” censoring rate = 0.15 “… Do you mean to say that 15% of your subjects are right censored?

How to simulate survival data with the SIM survdata function?

The coefficients and the covariates together form values of the linear predictor, contained in the xb attribute, and exponentiated values of the linear predictor, contained in the exp.xb attribute: In the course of generating simulations, the flexible-hazard method requires expressing each individual observation’s survivor function.

Where is the full survival dataset stored?

The full survival dataset, including the durations ( y ), the censoring variable ( failed ), and the covariates, is contained in the data frame object stored in the data attribute: The xdata attribute only contains the covariates:

Is it possible to have a 15% censoring rate?

Having stipulated any three, the last is necessarily fixed. This fails; it seems that it is impossible to have a 15% censoring rate at a censoring time of .88 with a Weibull distribution where the scale parameter is held at 1, no matter what the shape parameter is.

When do you censor the size of an experiment?

That is typically taken to mean that the experiment is run for a period of time, and that whichever study units have not had the event by then are censored. If that is what you meant, then it is not (necessarily) possible to stipulate the shape and scale parameters, and the censoring time and rate simultaneously.