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How to get a variable inside a quote in Bash?
Any of the following should work for getting access to shell variables inside quotes: Use of single quotes is the main issue. According to the Bash Reference Manual: Enclosing characters in single quotes ( ‘) preserves the literal value of each character within the quotes.
How is the name of a variable expanded in Bash?
Bash uses the value of the variable formed from the rest of parameter as the name of the variable; this variable is then expanded and that value is used in the rest of the substitution, rather than the value of parameter itself.
What happens if I substitute value in place of variable?
If I substitute the value in place of the variable the command is executed just fine. Please tell me where am I going wrong. Inside single quotes everything is preserved literally, without exception. That means you have to close the quotes, insert something, and then re-enter again. Word concatenation is simply done by juxtaposition.
How to use double quotes in a variable?
You could used double quotes around your command, and then use whatever single and double quotes you need inside provided you escape double ones. use printf to replace the variable token with the expanded variable. Variables can contain single quotes.
How are variables quoted in single quoted here strings?
In single-quoted here-strings, variables are interpreted literally and reproduced exactly. For example: @’ The $profile variable contains the path of your PowerShell profile. ‘@ The output of this command is: The $profile variable contains the path of your PowerShell profile. In double-quoted here-strings, variables are replaced by their values.
Can a double quoted string expand a variable?
ANSWER: Double quoted string expand variables and single quoted strings do not. PSMDTAG:FAQ: How do variables expand in strings? PSMDTAG:FAQ: Why don’t properties work with variable expansion in strings?
How to use variables inside single quotes-Unix?
For instance: command -p “cluster=cl1” is not accepted It looks like your command is maybe setting environment variables based on arguments given it on the command-line. It may be you can do: …and set its environment for it at invocation.