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How to move odd numbers after even numbers in singly linked list?
Given a singly linked list, we have to modify it such that all even numbers appear before odd numbers. From the above figure, we can see how the function will work. While the head of the list is odd, the head is copied to an auxiliary node and element next to the head will become the new head.
How to get even numbers in linked list?
Given a Linked List of integers, write a function to modify the linked list such that all even numbers appear before all the odd numbers in the modified linked list. Also, keep the order of even and odd numbers same. The idea is to get pointer to the last node of list.
How to segregate odd and even nodes in a linked list?
Segregate even and odd nodes in a Linked List Given a Linked List of integers, write a function to modify the linked list such that all even numbers appear before all the odd numbers in the modified linked list. Also, keep the order of even and odd numbers same. Examples:
How to keep even and odd numbers the same?
Also, keep the order of even and odd numbers same. The idea is to get pointer to the last node of list. And then traverse the list starting from the head node and move the odd valued nodes from their current position to end of the list.
How to keep even and odd nodes in a linked list?
At the end of loop, the original list will have all the even nodes and the odd node list will have all the odd nodes. To keep the ordering of all nodes same, we must insert all the odd nodes at the end of the odd node list. And to do that in constant time, we must keep track of last pointer in the odd node list.
Do you keep even and odd numbers the same?
Also, keep the order of even and odd numbers same. Recommended: Please solve it on “ PRACTICE ” first, before moving on to the solution. The idea is to get pointer to the last node of list.