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How to output only captured groups with SED?
You can use ripgrep, which also seems to be a sed replacement for simple substitutions, like this where ripgrep uses -o or –only matching and -r or –replace to output only the first capture group with $1 (quoted to be avoid intepretation as a variable by the shell) two times due to two matches.
How to do regex match groups using SED?
Is there anyway you can do regex match group using sed like java regex pattern/match/group? I am wondering does sed allow you to do something like java regex, you define the pattern like: EDIT: Also note just before SNAPSHOT that [.] will not match. Inside brackets . is literal. It should be [0-9.-]*
Do you use capture groups sequentially or sequentially?
We can’t give you a full answer without an example of your input but I can tell you that your understanding of capture groups is wrong. You don’t use them sequentially, they only refer to the regex on the left hand side of the same substitution operator.
How to replace regex capture group content using SED?
I’m trying to edit my nginx.conf file programmatically, which contains a line like this: I believe the regex ^\\s*access_log ( [^;]*); will capture the /var/log/nginx/access.log part in a capture group, but I’m not sure how to correctly replace the capture group with sed?
Why do I need to escape regex characters in SED?
The -r switch enables extended regular expressions which is why you don’t get the error. See Why do I need to escape regex characters in sed to be interpreted as regex characters?. Second, you are putting the capture group in the wrong place. If I understand you correctly, you can do this:
Can you use any character as a separator in SED?
It’s a not-so-known fact that sed can use any character as separator for the “s” command. Basically, sed takes whatever follows the “s” as the separator. So, our code above can be rewritten for example in one of the following ways:
Do you split a string by semicolon or delimiter?
Although as stated in my comment, you should just split the string by semicolon and grab the 4th element of the split…that’s the whole point of a delimited file, is you don’t need complex pattern matching. Similar to Anirudha’s answer but a little simpler.