How to replace the last occurrence of string in sed?
The following `sed` command will search the word ‘Jun’ in the string and replace the last occurrence of the word with the value, ‘May’. The following output will appear after running the command. Here, the word ‘Jun’ exists two times in the string, and the last occurrence has been replaced by the word ‘May’.
How do I change the second occurrence of a string in Linux?
- Replacing or substituting string : Sed command is mostly used to replace the text in a file.
- Replacing the nth occurrence of a pattern in a line : Use the /1, /2 etc flags to replace the first, second occurrence of a pattern in a line.
How do you change the last line of a file in Unix?
Breaking that apart:
- -i = edit the file “in-place”
- $(( )) = do some math:
- $( wc -l < input) = get the number of lines in the file.
- -n + 1 = go backwards n-1 lines.
- ,\$ = from n-1 lines until the end of the file:
- s/,/;/g = replace the commas with semicolons.
How to replace the last occurrence in a string?
`sed` command can be used to replace any part of a string or a line of the file in different ways by using regular expression patterns. This tutorial showed the ways to replace the last occurrence of the searching text in a string or a file by using multiple `sed` commands.
When to use sed to replace second occurrence of a word?
But from the output, you can see that ‘sed’ is not replacing 2nd occurrence of the world ‘line’. So, am I making any mistake here? s/../../2 is replacing the second occurrence of each line. The 2s is to make the change on the second line. Your command would only work if the string line appeared more than once on one or more lines.
How to replace the last occurrence of character in Bash?
In bash (assuming the string doesn’t contain byte sequences not forming valid characters in the current locale): $ {str%\\|*} expands to the string with the last | and everything after it removed.
How to replace a string variable in Linux?
To replace it in a multiline string shell variable, with GNU sed, you can use the -z option which treats the input as NUL delimited instead of newline delimited: var=$ (printf %s “$var” | sed -z ‘…’)