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How to solve the HackerRank climbing the leaderboard problem?
I am solving the following Hackerrank problem: Climbing the Leaderboard. Alice is playing an arcade game and wants to climb to the top of the leaderboard and wants to track her ranking. The game uses Dense Ranking, so its leaderboard works like this:
How to climb the leader board in Java?
For example, the four players on the leaderboard have high scores of 100, 90, 90, and 80. Those players will have ranks 1, 2, 2, and 3, respectively. If Alice’s scores are 70, 80 and 105, her rankings after each game are 4th, 3rd and 1st. Complete the climbingLeaderboard function in the editor below.
How to climb to the top of the leaderboard?
Climbing the Leaderboard HackerRank Solution in C, C++, Java, Python January 15, 2021 by ExploringBits An arcade game player wants to climb to the top of the leaderboard and track their ranking. The game uses Dense Ranking, so its leaderboard works like this:
How does the leaderboard work in arcade games?
An arcade game player wants to climb to the top of the leaderboard and track their ranking. The game uses Dense Ranking, so its leaderboard works like this: The player with the highest score is ranked number on the leaderboard.
How to climb the leaderboard in JavaScript?
You are given an array, scores, of monotonically decreasing leaderboard scores, and another array, alice, of Alice’s cumulative scores for each level of the game. You must print m integers. The jth integer should indicate the current rank of alice after passing the jth level.
What is the complexity of climbing the leaderboard?
Well, when you include the complexity of finding the distinct set of Leaderboard scores, the total complexity is O (n + m*log (n)), assuming n is much larger than m. what is the method “of (scores)”?
Do you need binary search to climb leaderboard?
It’s not quite THE way to do it. Binary search is not needed because Alice’s scores are strictly ascending. You only need to start at the bottom of the leaderboard and move up as necessary. This changes the complexity from O (n+m*log (n)) to O (n+m) and the code is even simpler.