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How to use multiple variables in single for loop in shell script?
Now as an answer to the question in the title, for a shell with for loops taking more than one variables, you’ve got zsh (you seem to already be using zsh syntax by not quoting your variables or not disabling globbing when splitting command substitution): You can store an output of a file in a variable and then break it into two. example:
How to loop through a variable in Bash?
But how to do it when they are 2? So script should loop each folder with correct mount added. You need to iterate over the array index number and not the value. This is done using the $ {!folder [@]} syntax.
How to use two variables in the same loop?
This might be another way to use two variables in the same loop. But you need to know the total number of files (or, the number of times you want to run the loop) in the directory to use it as the value of iteration i. For more help please see this discussion.
When to use for loop instead of while loop?
This version uses a for loop instead of a while loop. This one stops when the shorter of the two lists run out. This version is similar to the one immediately above, but if one of the lists runs out it wraps around to reuse the items until the other one runs out.
What are the three parameters of Bash for loops?
To fix this problem use three-expression bash for loops syntax which share a common heritage with the C programming language. It is characterized by a three-parameter loop control expression; consisting of an initializer (EXP1), a loop-test or condition (EXP2), and a counting expression (EXP3):
How is a while loop represented in shell scripting?
The while loop syntax in the shell scripting will be represented in the following way. In the above syntax, initially, the condition will be evaluated if it is true then the commands inside the loop will execute until the condition remains true else it will come outside of the loop. Here while, do, and done are built-in keywords.