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What causes a function to exit in Bash?
Causes a function or sourced script to exit with the return value specified by N. If N is omitted, the return status is that of the last command executed within the function or script. Exit Status: Returns N, or failure if the shell is not executing a function or script.
How to capture the exit status in Bash?
Bonus: in the end the exit status is actually an exit status and not some string in a file. you want the exit status from someprog and the output from filter. ( ( ( (someprog; echo $? >&3) | filter >&4) 3>&1) | (read xs; exit $xs)) 4>&1 echo $?
When does a Bash function end its return value?
When a bash function ends its return value is its status: zero for success, non-zero for failure. To return values, you can set a global variable with the result, or use command substitution, or you can pass in the name of a variable to use as the result variable. The examples below describe these different mechanisms.
How to capture remote script output and exit?
I wish to use shell to invoke a script on a remote server. I would like to capture the output of that script (its logging messages) and the exit code it returns. ssh user@server /usr/local/scripts/test_ping.sh echo “$?” I get the exit code but can’t capture the remote logging messages .
When to use return instead of continue in Bash?
SC2104: In functions, use `return` instead of `continue`. And the shellcheck wiki says don’t do it. But is there a way? Thanks everyone for the answers so far.
What happens if I invoke a script in Bash?
But if you invoke an executable script (i.e., directly with its filename), the return statement will result in a complain (error message “return: can only `return’ from a function or sourced script”).
Why is the return status 0 in Bash?
The strange behavior conforms to the documentation of local within the man page of bash: “The return status is 0 unless local is used outside a function, an invalid name is supplied, or name is a readonly variable.” Though not being a bug I feel that the behaviour of bash is counterintuitive.
How to exit the shell function not the terminal?
If you had launched your script like bash ./ (or any other shell instead of bash ), then exit would have stopped your child shell and not the one used by your terminal. If your script has executable permissions, executing it directly without giving the name of the shell will execute it in a child shell too.
How to exit Bash with the return value n?
As §4.1 “Bourne Shell Builtins” of the Bash Reference Manual puts it: Cause a shell function to exit with the return value n. If n is not supplied, the return value is the exit status of the last command executed in the function.
Is there any way to exit a script and then stay in the terminal?
When I use exit command in a shell script, the script will terminate the terminal (the prompt). Is there any way to terminate a script and then staying in the terminal? My script run.sh is expected to execute by directly being sourced, or sourced from another script. EDIT: To be more specific, there are two scripts run2.sh as