What does %d mean in Bash?
-d $directory ] means if $directory does not exist, or $directory isn’t a directory (maybe a file instead). Usually this is followed by a statement to create the directory, such as if [ ! – d $directory ]; then mkdir $directory fi.
How do I print a file size in Bash?
Getting file size using find command find “/etc/passwd” -printf “%s” find “/etc/passwd” -printf “%s\n” fileName=”/etc/hosts” mysize=$(find “$fileName” -printf “%s”) printf “File %s size = %d\n” $fileName $mysize echo “${fileName} size is ${mysize} bytes.”
How to count files and directories using BASH script?
I’m learning bash scripting and have written a script to count the files and directories in the directory that is supplied as argument. I have it working one way which seems odd to me and am wondering if there is a simpler way of doing it. I have commented out the code that will work, but left it in as a comparison.
How to print the invalid number in Bash?
As you can see in the above example, if it doesn’t find intended arguments, it displays the default values which is null for strings and 0 for integers. printf “Hi %s, your room number is %d. ” Abhishek Prakash 131 bash: printf: Prakash: invalid number Hi Abhishek, your room number is 0. Hi 131, your room number is 0.
Can you guess the output of the Bash printf command?
The bash printf command operates like the printf command in C/ C++ programming language. Can you guess the output? The first argument %s expects a string, %d expects a decimal integer, just like C/C++. Don’t worry if you are not familiar with C/C++. You don’t need to learn it just for using printf command in your Bash scripts.
What is the width modifier in Bash printf?
The width modifier is a integer that specifies the minimum field width of the argument. You can use the precision modifier (.) dot to specify a minimum number of digits to be displayed with %d, %u, %o, %x. It adds zero padding on the left of the value.