What is loading effect of voltage divider bias?
Loading Effects of Voltage-Divider Bias When the emitter resistor is viewed from the base circuit, the resistor appears to be larger than its actual value because of the dc current gain in the transistor.
How does a voltage divider behave in the loaded state?
The voltage divider can be loaded by connecting it to a load (resistor RL in the diagram below). This load resistance conducts a load current IL, while resistor R2 conducts a parallel current IQ. The value for the unloaded state is derived by letting the load resistance RL approach infinity. …
Is the output of a voltage divider affected by load resistance?
It’s easy to see in the equivalent circuit that an added load R L forms a voltage divider with the equivalent resistance and so, the voltage across R L must be less than 24V: Yes, loading the output of a voltage divider will lower the output voltage. One way to look at this is to characterize the voltage source produced by the voltage divider.
Why do you get more power with a voltage divider?
You would find upon exploration that for a given set of values for the voltage divider (R1and R2), you will get more power to the load if you decrease the load resistor RLbut is comes at the expense of higher current and power from the power supply.
Is the 24 V output affected by load resistance?
It will be 24 V with 0 current. Any current drawn will also flow thru R1, which causes a voltage drop accross R1, which subtracts from the 24 V source voltage as seen by the output. This relationship is linear. We already have the point with 0 current. Another point that gives us some intuition is the 0 voltage case.
Which is larger R1 or R2 in a voltage divider?
One practical consideration is that a larger value of R2compared to R1will give you a larger output voltage. But if your load resistance RLis smaller than R2, you will diminish the output voltage and require a larger current and total power from the power supply.