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What is the Dining Philosophers problem in OS?
The Dining Philosophers problem is a classic OS problem that’s usuallu stated in very non-OS terms: There are N philosphers sitting around a circular table eating spaghetti and discussing philos- phy. The problem is that each philosopher needs 2 forks to eat, and there are only N forks, one between each 2 philosophers.
How many dining philosophers can eat simultaneously?
This implies that no neighboring philosophers can eat at the same time and at most two philosophers can eat at a time. This model executes until deadlock occurs (or until you push the stop button). Deadlock occurs when each of the philosophers acquires one chopstick.
How can we prevent deadlock in Dining philosophers Problem?
Strategy: Every philosopher must request each of their (shared) chopsticks from a waiter, who may refuse the request at first in order to avoid a deadlock. For convenience, we assume that all philosophers request their left chopstick first, then their right chopstick.
What is the solution to the dining philosophers problem?
The dining philosopher is a classic synchronization problem as it demonstrates a large class of concurrency control problems. Solution of Dining Philosophers Problem A solution of the Dining Philosophers Problem is to use a semaphore to represent a chopstick.
Is the dining philosophers problem a concurrency problem?
The dining philosopher demonstrates a large class of concurrency control problems hence it’s a classic synchronization problem. Dining Philosophers Problem – Let’s understand the Dining Philosophers Problem with the below code, we have used fig 1 as a reference to make you understand the problem exactly.
How are semaphores used in the dining philosophers problem?
We use a semaphore to represent a chopstick and this truly acts as a solution of the Dining Philosophers Problem. Wait and Signal operations will be used for the solution of the Dining Philosophers Problem, for picking a chopstick wait operation can be executed while for releasing a chopstick signal semaphore can be executed.
How many philosophers should be on the table?
There should be at most four philosophers on the table. An even philosopher should pick the right chopstick and then the left chopstick while an odd philosopher should pick the left chopstick and then the right chopstick. A philosopher should only be allowed to pick their chopstick if both are available at the same time.