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What is the Nyquist sampling rate for a low-pass signal with bandwidth of 200 kHz?
400,000 samples per second
Solution The bandwidth of a low-pass signal is between 0 and f, where f is the maximum frequency in the signal. Therefore, we can sample this signal at 2 times the highest frequency (200 kHz). The sampling rate is therefore 400,000 samples per second.
How do you find the maximum and minimum frequency?
Calculating Maximum Frequency for an Application
- Device used: DS1020-100. Desired delay: 25 ns. Minimum pulse width = 25 ns + 12 ns = 37 ns. Maximum allowable input frequency = 1/(2 * 37 ns) = 18.52 MHz.
- Device used: DS1023-500. Desired delay: 60 ns. Minimum pulse width = 22 ns + 60 ns = 82 ns.
What is the Nyquist frequency of a voice signal?
“A voice signal is band-limited to 3.3 kHz. What is the Nyquist frequency? It is sampled using a guard band of 1.4 kHz is applied and converted to digital data with 7 bits per sample. What is the resulting data rate?” f N y = 1 2 f s = 1 2 3300 Hz = 1650 Hz.
Is the voice signal limited to 3.3 kHz?
A voice signal is band-limited to 3.3 kHz. What is the Nyquist frequency? I’m having a some trouble with an assignment I have to do. I don’t come from electrical engineering background and would appreciate any help I can get. “A voice signal is band-limited to 3.3 kHz. What is the Nyquist frequency?
What is the difference between Nyquist rate and sampling rate?
Nyquist rate is the sampling rate needed to record signal well given a certain maximum frequency in a signal. given sampling rate = nyquist frequency * 2 nyquist rate = given max frequency * 2
Which is the main carrier of a 12 kHz voice signal?
Twelve voice signals, each band-limited to 3 kHz, are frequency -multiplexed using 1 kHz guard bands between channels and between the main carrier and the first channel. The modulation of the main carrier is AM.