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What is the power dissipated in the 30 resistor?
The power dissipated by the 30 Ω resistor is P30 = (100 V)2/(30 Ω) = 333.3 W. The total power dissipated by the two resistors is 1000 W, the same as through their equivalent resistor.
What happens to the power dissipated by a resistor as the current through the resistor increases?
The unit of power is the Watt (W). When the voltage is increased, the current, I, increases and the power dissipated by the resistor, R, increases. When the value of the resistor is increased, I decreases and the power dissipated by the resistor, R, decreases.
How can you define power dissipation in a resistor?
Power dissipation of a resistor or any load is the amount of power (in watts) that is converted to heat, light, or other form of energy. In a resistor, power dissipation is defined by Ohm’s law P = I^2 * R Power dissipated equals current through the resistor squared times the resistance in ohms.
How does a resistor dissipate power?
Power Dissipation in Resistors. Any resistor in a circuit that has a voltage drop across it dissipates electrical power. This electrical power is converted into heat energy hence all resistors have a power rating. This is the maximum power that can be dissipated from the resistor without it burning out.
What is the equation for power dissipated in a circuit?
If a current I flows through through a given element in your circuit, losing voltage V in the process, then the power dissipated by that circuit element is the product of that current and voltage: P = I × V .
What is the total power dissipated in the circuit?
The meaning of total power dissipated in AC circuit is same as power dissipated on any circuit- which is the work done per unit time by source to move charges in a circuit. For DC we have Power = Voltage*Current. Since, voltage gives the work done per unit charge, multiplying it by current which is charge/time gives power.