What is the probability of having different birthdays?

What is the probability of having different birthdays?

(c) Now add a fourth person, and a fifth, and so on until you have 22 people with different birthdays (p ≈ 52.4%). When you add the 23rd person, you should have p ≈ 49.3%….Probability of Shared Birthdays. or, How to Win Money in Bar Bets.

Probability in a group of n people that 2 or more have the same birthday
50	0.970

What is the probability that 2 friends have different birthdays?

The probability that two different friend have different birthdays (ignoring a leap year) is : a) 364/365.

What is the probability that two randomly chosen students have their birthday in the same month?

The probability that any randomly chosen 2 people share the same birthdate. So you have a 0.27% chance of walking up to a stranger and discovering that their birthday is the same day as yours. That’s pretty slim.

What is the probability that the birthdays of three people fall in the same month?

This is the case as irrespective of which month the first person is born in, the birthday of the second can be in the remaining 11 months and the third can be born in any of the remaining 10 months. There is a probability of 17/72 that the three are born in the same month.

What is the probability of two people being born in the same month?

The probability of you walking into a room and the one person already in the room having a different birth month is 11/12 (assuming birthdays are equally likely in each of 12 months). The probability of the birthdays being in the same month is 1/12 (or, 1 – 11/12).

What is the probability of two persons being born on the same day ignoring date?

∴ Probability = 7/49 = ”1/7” Thus (c) is the answer. Thanks for marking it as the brainliest.

What’s the probability of two people being born in the same month?

1/12 probability
Let the first person’s birth month be x. Now, the second person must born in the same month (1/12 probability) to satisfy the given condition as both their births are independent events. So, required probability is 1/12 . So, 5 is the answer.

How to find the probability of 6 different birth days?

Find the probability that the birth days of 6 different persons will fall in exactly two calendar months. Here each person has 12 option So there are 6 persons .total no. Of ways 12^6

How many bdays can fall in one month?

Anyone’s bday can fall in any of the months…hence sample space is 12^6… Now selecting any 2 months from 12 months in 12 C 2 ways out of which there is a possibility that all of them have their bday in a single month…hence favourable outcome= 12 C 2 ∗ ( 2 6 − 2)

What is the probability of the string of birthmonths?

And for each choice of other month, there are 2 5 − 1 ways the string of birthmonths can be completed to yield a favourable, for not everybody can choose the same month as the shortest person. This gives a total of ( 11) ( 31) = 341 favourables. Thus the required probability is 341 12 5.