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What is the range of the cannonballs?
Given the initial speed of the cannonball and the angle at which it was shot, can you determine how far it will travel? So there you have it — now you can figure out the range of the cannon given the speed of the cannonball and the angle at which it was shot. Your range is 75 kilometers, or nearly 47 miles.
What is the cannonballs maximum height?
Note also that the maximum height depends only on the vertical component of the initial velocity, so that any projectile with a 67.6 m/s initial vertical component of velocity will reach a maximum height of 233 m (neglecting air resistance).
What is the best angle to throw a ball at for maximum range?
45 degrees
A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.
How many mph does a cannonball go?
The Cannonball Run: A journey and a race, run at warp speed. Or about 80 mph. Police officers often know cars well, Tabbutt said, but the countermeasures are designed to confuse even if just for a moment, which could make the difference if they are pulled over.
What is the greatest height reached by the ball?
Derive the formula for the maximum height reached during upward movement when a ball is thrown vertically upward? Therefore if a ball is thrown vertically upwards with 98 m/s velocity, the maximum height reached by it would be = (98 x98 )/(2 x 9.8) meter = 490 meters.
How do you find the maximum height in free fall?
y = v 0 2 − 2 g = ( 2.0 × 10 2 m / s ) 2 − 2 ( 9.8 m / s 2 ) = 2040.8 m . This solution gives the maximum height of the booster in our coordinate system, which has its origin at the point of release, so the maximum height of the booster is roughly 7.0 km.
What is the formula of horizontal range?
Range. The range of the motion is fixed by the condition y=0 . Using this we can rearrange the parabolic motion equation to find the range of the motion: R=u2⋅sin2θg R = u 2 ⋅ sin 2 θ g .
Why is 45 degrees the maximum range?
The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.
At what angle should the ball be kicked?
That means that the best way to launch a high-altitude projectile is to send it flying at a 90-degree angle to the ground—straight up.