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Which command within a shell script awaits user input and places that input into a variable?
Read user input in shell script User input will be stored in a variable named message . This will print a message on the terminal asking the user to enter some input and will store the input in message variable.
Which command is used to display variable values in Unix?
Explanation: set command is used to display all the variables available in the current shell. set is a built-in command. env is an external command and runs in a child process. It thus displays only those variables that are inherited from its parent, the shell.
How to read multiple variables with READ command?
I want to read multiple variables using single read command in shell script. So i tried as below: but it’s not working. It just ask for single value of P variable and returns prompt. I googled it but don’t found any solution.
Where does the READ command store the input?
By default the read command will take input from stdin (standard input) and store it in a variable called $REPLY. The default delimiter for read is a newline, so it will accept input until you hit the enter key. Store Input in a Variable Read always stored your input in a variable.
How to use multiple variable for input in Bash?
So, here the user must enter the values for P, N, R space or tab separated, like: (here we didn’t bother escaping the spaces for R as the rest of the line after the third word would end-up in R anyway; the user would still need to escape a trailing space though).
How does read store input in a variable?
Read always stored your input in a variable. As mentioned above it uses $REPLY for the default variable. If you want to store the input into a user defined variable, you can simply invoke the read command with a single argument. Instead of the default $REPLY variable, read will use the argument you supply.