Why does the inverting amplifier output voltage saturate?

Why does the inverting amplifier output voltage saturate?

Some of this output voltage is returned back to the input by the feedback network. Thus the input voltage becomes more positive, causing an even larger output voltage and so on. Eventually the output becomes saturated at its positive supply rail.

What is the output impedance of an inverting op amp?

0
The output impedance of an ideal op amp is 0. This means that regardless of the amount of current drawn by an external load, the output voltage of the op amp remains unaffected.

What is saturated output voltage?

When the output voltage implied by the circuit would exceed the possible range, the op-amp is said to saturate, and it just outputs its maximum or minimum possible voltage instead. We often call the supply voltages the rails.

How is an inverting amplifier used in a circuit?

Another use of Inverting amplifier is using the amplifier as Trans-Impedance Amplifier. In such circuit, the op-amp converts very low input current to the corresponding output voltage. So, a Trans-Impedance amplifier converts current to voltage.

How to calculate the output impedance of an amplifier?

The Output Impedance of an amplifier can be thought of as being the impedance (or resistance) that the load sees “looking back” into the amplifier when the input is zero. Working on the same principle as we did for the input impedance, the generalised formula for the output impedance can be given as: ZOUT = VCE/IC.

How is the voltage of an inverting op amp adjusted?

The input current flows through Rf and creates a voltage drop VRf = Iin.Rf. To keep the voltage at the inverting input equal to zero (obbeying the so-called “golden rule”), the op-amp adjusts its output voltage equal to the voltage drop across Rf (Vout = -Iin.Rf) and adds it in series.

Is the impedance of the op amp infinite?

Yes, this is the circuit input impedance (between the left Rin end and ground) that is different from the op-amp input impedance (between its two inputs). It seems to me that it should be infinite because the impedance between the op amp inputs is infinite. Really, the op-amp input impedance is infinite… but if the op-amp was standalone.